pyspark.pandas.Index.rename¶

Index.rename(name: Union[Any, Tuple[Any, …], List[Union[Any, Tuple[Any, …]]]], inplace: bool = False) → Optional[pyspark.pandas.indexes.base.Index][source]¶

Alter Index or MultiIndex name. Able to set new names without level. Defaults to returning new index.

Parameters

namelabel or list of labels: Name(s) to set.
inplaceboolean, default False: Modifies the object directly, instead of creating a new Index or MultiIndex.

Returns

Index or MultiIndex: The same type as the caller or None if inplace is True.

Examples

>>> df = ps.DataFrame({'a': ['A', 'C'], 'b': ['A', 'B']}, columns=['a', 'b'])
>>> df.index.rename("c")
Int64Index([0, 1], dtype='int64', name='c')

>>> df.set_index("a", inplace=True)
>>> df.index.rename("d")
Index(['A', 'C'], dtype='object', name='d')

You can also change the index name in place.

>>> df.index.rename("e", inplace=True)
>>> df.index
Index(['A', 'C'], dtype='object', name='e')

>>> df  
   b
e
A  A
C  B

Support for MultiIndex

>>> psidx = ps.MultiIndex.from_tuples([('a', 'x'), ('b', 'y')])
>>> psidx.names = ['hello', 'pandas-on-Spark']
>>> psidx  
MultiIndex([('a', 'x'),
            ('b', 'y')],
           names=['hello', 'pandas-on-Spark'])

>>> psidx.rename(['aloha', 'databricks'])  
MultiIndex([('a', 'x'),
            ('b', 'y')],
           names=['aloha', 'databricks'])

pyspark.pandas.Index.map pyspark.pandas.Index.repeat